Optimal. Leaf size=65 \[ \frac {2 b \, _2F_1\left (1,\frac {1}{4} (2+3 p);\frac {3 (2+p)}{4};-\tan ^2(c+d x)\right ) \tan ^{1+p}(c+d x) \sqrt {b \tan ^p(c+d x)}}{d (2+3 p)} \]
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Rubi [A]
time = 0.03, antiderivative size = 65, normalized size of antiderivative = 1.00, number of steps
used = 3, number of rules used = 3, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {3740, 3557,
371} \begin {gather*} \frac {2 b \tan ^{p+1}(c+d x) \sqrt {b \tan ^p(c+d x)} \, _2F_1\left (1,\frac {1}{4} (3 p+2);\frac {3 (p+2)}{4};-\tan ^2(c+d x)\right )}{d (3 p+2)} \end {gather*}
Antiderivative was successfully verified.
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Rule 371
Rule 3557
Rule 3740
Rubi steps
\begin {align*} \int \left (b \tan ^p(c+d x)\right )^{3/2} \, dx &=\left (b \tan ^{-\frac {p}{2}}(c+d x) \sqrt {b \tan ^p(c+d x)}\right ) \int \tan ^{\frac {3 p}{2}}(c+d x) \, dx\\ &=\frac {\left (b \tan ^{-\frac {p}{2}}(c+d x) \sqrt {b \tan ^p(c+d x)}\right ) \text {Subst}\left (\int \frac {x^{3 p/2}}{1+x^2} \, dx,x,\tan (c+d x)\right )}{d}\\ &=\frac {2 b \, _2F_1\left (1,\frac {1}{4} (2+3 p);\frac {3 (2+p)}{4};-\tan ^2(c+d x)\right ) \tan ^{1+p}(c+d x) \sqrt {b \tan ^p(c+d x)}}{d (2+3 p)}\\ \end {align*}
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Mathematica [A]
time = 0.08, size = 60, normalized size = 0.92 \begin {gather*} \frac {2 \, _2F_1\left (1,\frac {1}{4} (2+3 p);\frac {3 (2+p)}{4};-\tan ^2(c+d x)\right ) \tan (c+d x) \left (b \tan ^p(c+d x)\right )^{3/2}}{d (2+3 p)} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.22, size = 0, normalized size = 0.00 \[\int \left (b \left (\tan ^{p}\left (d x +c \right )\right )\right )^{\frac {3}{2}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (b \tan ^{p}{\left (c + d x \right )}\right )^{\frac {3}{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int {\left (b\,{\mathrm {tan}\left (c+d\,x\right )}^p\right )}^{3/2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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